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## How is the lighting load in amperes determined?

To find the general lighting load, the outside dimensions must be multiplied by a unit load of 3 volt-amperes per square foot. With a voltage of 120/240, the general lighting load is 48 amperes (5,775 ÷ 120 = 48). To find the minimum number of 15-amperes, 2-wire circuits, divide 48 by 15 (48 ÷ 15 = 3.2 = 4).

## How do you find volt-amperes?

Using this formula, volt-amps can be found by multiplying volts times amps. For example, let’s find the volt-amps for a single-phase circuit with 20 amps of current at 120 volts. So, a 120 volt circuit with 20 amps of current should have 2,400 volt-amps of apparent power.

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## How do you calculate lighting loads?

To calculate the lighting load, we use this formula:

1. Watts = Volts * Amps (or W=VA in short).
2. For example:
3. 240 Volts * 20 Amps = 4800 Watts.
4. Knowing this tiny bit of information helps you to know how much power you can draw without tripping your circuit breaker.

## How many outlets can be lighted on one branch?

Although there’s no limit on the number of lighting and/or receptacle outlets on dwelling general-purpose branch circuits, the NEC does require a minimum number of circuits to be installed for general-purpose receptacles and lighting outlets [210.11(A)].

## How do you calculate lighting for an area?

Lighting Calculation – Summary Calculate the amount of lumens you need. Multiply the area in square meters by the lux, or the area in square feet by the footcandles. work out how many bulbs you need. Divide the number of lumens by the number of lumens delivered by each bulb.

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## What does the code state for how much power is needed to run general lighting loads in dwelling?

The general calculated load must be at least 100% for the first 10kVA, plus 40% of the remainder of the following loads: General lighting and receptacles: 3VA per sq ft. Small-appliance and laundry branch circuits: 1,500VA for each 20A, 120V small-appliance and laundry branch circuit specified in 220.52.

## What’s the minimum voltage for a lighting circuit?

The minimum lighting load for this dwelling is 5,775 volt-amperes (55 x 35 x 3 = 5,775). With a voltage of 120/240, the general lighting load is 48 amperes (5,775 ÷ 120 = 48). To find the minimum number of 15-amperes, 2-wire circuits, divide 48 by 15 (48 ÷ 15 = 3.2 = 4).

## How to calculate the lighting load for a house?

To find the general lighting load, the outside dimensions must be multiplied by a unit load of 3 volt-amperes per square foot. The minimum lighting load for this dwelling is 5,775 volt-amperes (55 x 35 x 3 = 5,775).