Mell How many bits are there in data inputs of the memory?
In the dummy program above we used a byte (eight bits) to represent each ‘chunk’ of information. Most computers now use 32 or 64 bits.
How many bits are there in the address part?
Each address identifies a single byte (eight bits) of storage. Data larger than a single byte may be stored in a sequence of consecutive addresses.
How many bits are there in register code path?
How many bits are there in operation code, the register code part and the address part ? OP-code 32 – 1 – 18 – 6 bits = 7 bits.
How many bits is the op code?
Given the instruction set of size 12, 4 bits are required for opcode (2^4 = 16). As there are total 64 registers, 6 bits are required for identifying a register.
How many bits are in a opcode?
8 bits
Code size: Each instruction has an opcode and a set of operands • The opcode is always 1 byte (8 bits). All register operands are 1 byte (8 bits). All memory addresses are 2 bytes (16 bits). All data operands are 4 bytes (32 bits).
What is the number of address bits needed for a 1 GB main memory?
210 = 1024, so you need 10 bits to address every byte in a kilobyte. Likewise, you need 20 bits to address every byte in a megabyte, and 30 bits to address every byte in a gigabyte.
What is an indirect bit?
One bit of the instruction code can be used to distinguish between a direct and an indirect address. It is sometimes convenient to use the address bits of an instruction code not as an address but as the actual operand.
How many bits are there in the Ethernet address?
The Ethernet address is 48 bits long and normally displayed as 12 hexadecimal digits.
How many bits’address is required for a computer with n bytes of memory?
Likewise, you need 20 bits to address every byte in a megabyte, and 30 bits to address every byte in a gigabyte. 2 32 = 4294967296, which is the number of bytes in 4 gigabytes, so you need a 32 bit address for 4 GB of memory. OK so for 512 Mbyte RAM the equation is 512*1024²=2^x(?) Thanks a lot for the prompt answer. – Niklas Dec 10 ’12 at 16:07
Which is an example of memory address in a computer?
Address Address Memory addressing Example – for a Computer – Word = 16 bits – Byte addressable – uses big-endian – Long word = 4 bytes – 24 bits used for address 16 M bytes or 8 M words Instructions and instruction sequencing 4 bits 12 bits Address Inf.
How many bits are needed for 4 GB of memory?
Likewise, you need 20 bits to address every byte in a megabyte, and 30 bits to address every byte in a gigabyte. 2 32 = 4294967296, which is the number of bytes in 4 gigabytes, so you need a 32 bit address for 4 GB of memory.
How to calculate memory size based on address?
Is that correct? Step 1: calculate the length of the address in bits (n bits) Step 2: calculate the number of memory locations 2^n (bits) Step 3: take the number of memory locations and multiply it by the Byte size of the memory cells.