Why emitter base junction is forward biased and collector base junction is reversed biased?
With the base-emitter junction is forward biased and the base-collector junction is reversed biased, the transistor can amplify voltage because the collector to emitter voltage is greater than the base to emitter voltage and is also in between the cutoff and saturation states.
What happens if the emitter is reverse biased?
What will happen if both, emitter and collector of a transistor are reversed biased? In this situation, on current will flow through transistor because there is no conduction due to majority carriers across the emitter-base junction or collector-base junction.
When emitter base junction is in forward bias and collector base junction is in reverse bias the BJT used as?
|Mode||Emitter Junction diode||Collector Junction diode|
|Saturation||Forward bias||Forward bias|
|Cut-off||Reverse bias||Reverse bias|
|Active||Forward bias||Reverse bias|
|Reverse Active||Reverse||Forward bias|
When emitter base junction is forward biased and collector base junction is reverse biased transistor is said to be in?
Active region is that region in which the emitter base junction is forward biased while the collector base junction is reverse biased. So, the correct answer is “Option B”.
What would happen if both junctions of a BJT are forward biased or reverse biased?
Answer: If both junctions are reverse biased the transistor is switch off since the currents will be very small in the order of the reverse saturation current and the reverse is true that is the transistor will be switch on and saturated when the 2 junctions are forward biased.
What happens if you reverse bias a transistor?
If you reverse bias the diode, the diode cuts off. Now, the base-emitter junction in a transistor is going to essentially turn the transistor on or off. Now, the base-collector junction will not have that same power, but the base-emitter junction will determine whether the transistor is turned on or off.
When both junctions are forward biased?
Saturation region is one in which both Emitter Base and Base Collector junctions of the transistor are forward biased. In this region high currents flows through the transistor, as both junctions of the transistor are forward biased and bulk resistance offered is very much less.
What happens if base emitter and base collector junctions are forward biased?
If the base current is increased further, the current through the resistor cannot increase, so the excess base current flows through the base-collector junction. Thus, both base-emitter and base-collector junctions are forward biased.
How can we say an emitter base is forward biased and base?
So in an NPN transistor a high voltage on the n-type collector and medium voltage on the p-type base and the lowest voltage on the n-type emitter results in a forward biased emitter base pn junction (higher voltage on p-base than n-emitter) and a reverse bias base collector junction (higher voltage on the n-collector than the
How does the reverse biased junction in a transistor work?
Here’s how it works: Current through the reverse biased junction in transistor. A transistor is a three terminal device. One terminal is called emitter, one collector and in between them is base. Now, during biasing the junction between emitter and base is made forward biased and the junction between collector and base is made reverse biased.
What happens if I bias the collector and emitter of an NPN?
As the collector doping is less than the emitter doping, the hole current in the collector (now the emitter) increases, leading to lower beta. (2). The voltage withstand capability goes down, as now the BE junction is reverse biased, and the emitter is not constructed for high withstand voltage.